In this section, you will:
The exterior of the Lincoln Memorial in Washington, D.C., is a large rectangular solid with length 61.5 meters (m), width 40 m, and height 30 m.1 We can easily find the volume using elementary geometry.
So the volume is 73,800 cubic meters
Suppose we knew the volume, length, and width. We could divide to find the height.
As we can confirm from the dimensions above, the height is 30 m. We can use similar methods to find any of the missing dimensions. We can also use the same method if any or all of the measurements contain variable expressions. For example, suppose the volume of a rectangular solid is given by the polynomial
The length of the solid is given by
the width is given by
To find the height of the solid, we can use polynomial division, which is the focus of this section.
We are familiar with the long division algorithm for ordinary arithmetic. We begin by dividing into the digits of the dividend that have the greatest place value. We divide, multiply, subtract, include the digit in the next place value position, and repeat. For example, let’s divide 178 by 3 using long division.
Another way to look at the solution is as a sum of parts. This should look familiar, since it is the same method used to check division in elementary arithmetic.
We call this the Division Algorithm and will discuss it more formally after looking at an example.
Division of polynomials that contain more than one term has similarities to long division of whole numbers. We can write a polynomial dividend as the product of the divisor and the quotient added to the remainder. The terms of the polynomial division correspond to the digits (and place values) of the whole number division. This method allows us to divide two polynomials. For example, if we were to divide
by
using the long division algorithm, it would look like this:
We have found
or
We can identify the dividend, the divisor, the quotient, and the remainder.
Writing the result in this manner illustrates the Division Algorithm.
The Division Algorithm states that, given a polynomial dividend
and a non-zero polynomial divisor
where the degree of
is less than or equal to the degree of
there exist unique polynomials
and
such that
is the quotient and
is the remainder. The remainder is either equal to zero or has degree strictly less than
If
then
divides evenly into
This means that, in this case, both
and
are factors of
Given a polynomial and a binomial, use long division to divide the polynomial by the binomial.
Divide
by
The quotient is
The remainder is 0. We write the result as
or
This division problem had a remainder of 0. This tells us that the dividend is divided evenly by the divisor, and that the divisor is a factor of the dividend.
Divide
by
There is a remainder of 1. We can express the result as:
We can check our work by using the Division Algorithm to rewrite the solution. Then multiply.
Notice, as we write our result,
Divide
by
As we’ve seen, long division of polynomials can involve many steps and be quite cumbersome. Synthetic division is a shorthand method of dividing polynomials for the special case of dividing by a linear factor whose leading coefficient is 1.
To illustrate the process, recall the example at the beginning of the section.
Divide
by
using the long division algorithm.
The final form of the process looked like this:
There is a lot of repetition in the table. If we don’t write the variables but, instead, line up their coefficients in columns under the division sign and also eliminate the partial products, we already have a simpler version of the entire problem.
Synthetic division carries this simplification even a few more steps. Collapse the table by moving each of the rows up to fill any vacant spots. Also, instead of dividing by 2, as we would in division of whole numbers, then multiplying and subtracting the middle product, we change the sign of the “divisor” to –2, multiply and add. The process starts by bringing down the leading coefficient.
We then multiply it by the “divisor” and add, repeating this process column by column, until there are no entries left. The bottom row represents the coefficients of the quotient; the last entry of the bottom row is the remainder. In this case, the quotient is
and the remainder is
The process will be made more clear in [link].
Synthetic division is a shortcut that can be used when the divisor is a binomial in the form
In synthetic division, only the coefficients are used in the division process.
Given two polynomials, use synthetic division to divide.
for the divisor.
Write the product in the next column.
Write the product in the next column.
Use synthetic division to divide
by
Begin by setting up the synthetic division. Write
and the coefficients.
Bring down the lead coefficient. Multiply the lead coefficient by
Continue by adding the numbers in the second column. Multiply the resulting number by
Write the result in the next column. Then add the numbers in the third column.
The result is
The remainder is 0. So
is a factor of the original polynomial.
Just as with long division, we can check our work by multiplying the quotient by the divisor and adding the remainder.
Use synthetic division to divide
by
The binomial divisor is
so
Add each column, multiply the result by –2, and repeat until the last column is reached.
The result is
The remainder is 0. Thus,
is a factor of
The graph of the polynomial function
in [link] shows a zero at
This confirms that
is a factor of
Use synthetic division to divide
by
Notice there is no x-term. We will use a zero as the coefficient for that term.* * *
The result is
Use synthetic division to divide
by
Polynomial division can be used to solve a variety of application problems involving expressions for area and volume. We looked at an application at the beginning of this section. Now we will solve that problem in the following example.
The volume of a rectangular solid is given by the polynomial
The length of the solid is given by
and the width is given by
Find the height of the solid.
There are a few ways to approach this problem. We need to divide the expression for the volume of the solid by the expressions for the length and width. Let us create a sketch as in [link].
We can now write an equation by substituting the known values into the formula for the volume of a rectangular solid.
To solve for
first divide both sides by
Now solve for
using synthetic division.
The quotient is
and the remainder is 0. The height of the solid is
The area of a rectangle is given by
The width of the rectangle is given by
Find an expression for the length of the rectangle.
Access these online resources for additional instruction and practice with polynomial division.
Division Algorithm |
where
If division of a polynomial by a binomial results in a remainder of zero, what can be conclude?
The binomial is a factor of the polynomial.
If a polynomial of degree
is divided by a binomial of degree 1, what is the degree of the quotient?
For the following exercises, use long division to divide. Specify the quotient and the remainder.
For the following exercises, use synthetic division to find the quotient.
For the following exercises, use synthetic division to determine whether the first expression is a factor of the second. If it is, indicate the factorization.
Yes
Yes
No
For the following exercises, use the graph of the third-degree polynomial and one factor to write the factored form of the polynomial suggested by the graph. The leading coefficient is one.
Factor is
Factor is
Factor is
Factor is
Factor is
For the following exercises, use synthetic division to find the quotient and remainder.
For the following exercises, use a calculator with CAS to answer the questions.
Consider
with
What do you expect the result to be if
Consider
for
What do you expect the result to be if
Consider
for
What do you expect the result to be if
Consider
with
What do you expect the result to be if
Consider
with
What do you expect the result to be if
For the following exercises, use synthetic division to determine the quotient involving a complex number.
For the following exercises, use the given length and area of a rectangle to express the width algebraically.
Length is
area is
Length is
area is
Length is
area is
For the following exercises, use the given volume of a box and its length and width to express the height of the box algebraically.
Volume is
length is
width is
Volume is
length is
width is
Volume is
length is
width is
Volume is
length is
width is
For the following exercises, use the given volume and radius of a cylinder to express the height of the cylinder algebraically.
Volume is
radius is
Volume is
radius is
Volume is
radius is
and a non-zero polynomial divisor
where the degree of
is less than or equal to the degree of
there exist unique polynomials
and
such that
where
is the quotient and
is the remainder. The remainder is either equal to zero or has degree strictly less than
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