In this section, you will:
Suppose a certain species of bird thrives on a small island. Its population over the last few years is shown in [link].
Year | $$2009$$ |
$$2010$$ |
$$2011$$ |
$$2012$$ |
$$2013$$ |
Bird Population | $$800$$ |
$$897$$ |
$$992$$ |
$$1,083$$ |
$$1,169$$ |
The population can be estimated using the function$\text{\hspace{0.17em}}P(t)=-0.3{t}^{3}+97t+800,\text{\hspace{0.17em}}$
where$\text{\hspace{0.17em}}P(t)\text{\hspace{0.17em}}$
represents the bird population on the island$\text{\hspace{0.17em}}t\text{\hspace{0.17em}}$
years after 2009. We can use this model to estimate the maximum bird population and when it will occur. We can also use this model to predict when the bird population will disappear from the island. In this section, we will examine functions that we can use to estimate and predict these types of changes.
Before we can understand the bird problem, it will be helpful to understand a different type of function. A power function is a function with a single term that is the product of a real number, a coefficient, and a variable raised to a fixed real number.
As an example, consider functions for area or volume. The function for the area of a circle with radius$\text{\hspace{0.17em}}r\text{\hspace{0.17em}}$
is
and the function for the volume of a sphere with radius$\text{\hspace{0.17em}}r\text{\hspace{0.17em}}$
is
Both of these are examples of power functions because they consist of a coefficient,$\text{\hspace{0.17em}}\pi \text{\hspace{0.17em}}$
or$\text{\hspace{0.17em}}\frac{4}{3}\pi ,\text{\hspace{0.17em}}$
multiplied by a variable$\text{\hspace{0.17em}}r\text{\hspace{0.17em}}$
raised to a power.
A power function is a function that can be represented in the form
where$\text{\hspace{0.17em}}k\text{\hspace{0.17em}}$
and$\text{\hspace{0.17em}}p\text{\hspace{0.17em}}$
are real numbers, and$\text{\hspace{0.17em}}k\text{\hspace{0.17em}}$
is known as the coefficient.
**Is$\text{\hspace{0.17em}}f(x)={2}^{x}\text{\hspace{0.17em}}$
a power function?**
No. A power function contains a variable base raised to a fixed power. This function has a constant base raised to a variable power. This is called an exponential function, not a power function.
Which of the following functions are power functions?
$$\begin{array}{cccc}\hfill f(x)& =& 1\hfill & \phantom{\rule{2em}{0ex}}\text{Constantfunction}\hfill \\ \hfill f(x)& =& x\hfill & \phantom{\rule{2em}{0ex}}\text{Identifyfunction}\hfill \\ \hfill f(x)& =& {x}^{2}\hfill & \phantom{\rule{2em}{0ex}}\text{Quadraticfunction}\hfill \\ \hfill f(x)& =& {x}^{3}\hfill & \phantom{\rule{2em}{0ex}}\text{Cubicfunction}\hfill \\ \hfill f(x)& =& \frac{1}{x}\hfill & \phantom{\rule{2em}{0ex}}\text{Reciprocalfunction}\hfill \\ \hfill f(x)& =& \frac{1}{{x}^{2}}\hfill & \phantom{\rule{2em}{0ex}}\text{Reciprocalsquaredfunction}\hfill \\ \hfill f(x)& =& \sqrt{x}\hfill & \phantom{\rule{2em}{0ex}}\text{Squarerootfunction}\hfill \\ \hfill f(x)& =& \sqrt[3]{x}\hfill & \phantom{\rule{2em}{0ex}}\text{Cuberootfunction}\hfill \end{array}$$All of the listed functions are power functions.
The constant and identity functions are power functions because they can be written as$\text{\hspace{0.17em}}f(x)={x}^{0}\text{\hspace{0.17em}}$
and$\text{\hspace{0.17em}}f(x)={x}^{1}\text{\hspace{0.17em}}$
respectively.
The quadratic and cubic functions are power functions with whole number powers$\text{\hspace{0.17em}}f(x)={x}^{2}\text{\hspace{0.17em}}$
and$\text{\hspace{0.17em}}f(x)={x}^{3}.$
The reciprocal and reciprocal squared functions are power functions with negative whole number powers because they can be written as$\text{\hspace{0.17em}}f(x)={x}^{-1}\text{\hspace{0.17em}}$
and$\text{\hspace{0.17em}}f(x)={x}^{-2}.$
The square and cube root functions are power functions with fractional powers because they can be written as$\text{\hspace{0.17em}}f(x)={x}^{\frac{1}{2}}\text{\hspace{0.17em}}$
or$\text{\hspace{0.17em}}f(x)={x}^{\frac{1}{3}}.$
Which functions are power functions?* * *
$\begin{array}{ccc}\hfill f(x)& =& 2x\cdot 4{x}^{3}\hfill \\ \hfill g(x)& =& -{x}^{5}+5{x}^{3}\hfill \\ \hfill h(x)& =& \frac{2{x}^{5}-1}{3{x}^{2}+4}\hfill \end{array}$is a power function because it can be written as$\text{\hspace{0.17em}}f(x)=8{x}^{5}.\text{\hspace{0.17em}}$
The other functions are not power functions.
[link] shows the graphs of$\text{\hspace{0.17em}}f(x)={x}^{2},\text{\hspace{0.17em}}g(x)={x}^{4}\text{\hspace{0.17em}}$
and$\text{\hspace{0.17em}}h(x)={x}^{6},\text{\hspace{0.17em}}$
which are all power functions with even, whole-number powers. Notice that these graphs have similar shapes, very much like that of the quadratic function in the toolkit. However, as the power increases, the graphs flatten somewhat near the origin and become steeper away from the origin.
To describe the behavior as numbers become larger and larger, we use the idea of infinity. We use the symbol$\text{\hspace{0.17em}}\infty \text{\hspace{0.17em}}$
for positive infinity and$\text{\hspace{0.17em}}\mathrm{-\infty}\text{\hspace{0.17em}}$
for negative infinity. When we say that “$x\text{\hspace{0.17em}}$
approaches infinity,” which can be symbolically written as$\text{\hspace{0.17em}}x\to \infty ,\text{\hspace{0.17em}}$
we are describing a behavior; we are saying that$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
is increasing without bound.
With the positive even-power function, as the input increases or decreases without bound, the output values become very large, positive numbers. Equivalently, we could describe this behavior by saying that as$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
approaches positive or negative infinity, the$\text{\hspace{0.17em}}f\left(x\right)\text{\hspace{0.17em}}$
values increase without bound. In symbolic form, we could write
[link] shows the graphs of$\text{\hspace{0.17em}}f(x)={x}^{3},\text{\hspace{0.17em}}g(x)={x}^{5},$
and$\text{\hspace{0.17em}}h(x)={x}^{7},$
which are all power functions with odd, whole-number powers. Notice that these graphs look similar to the cubic function in the toolkit. Again, as the power increases, the graphs flatten near the origin and become steeper away from the origin.
These examples illustrate that functions of the form$\text{\hspace{0.17em}}f\left(x\right)={x}^{n}\text{\hspace{0.17em}}$
reveal symmetry of one kind or another. First, in [link] we see that even functions of the form$\text{\hspace{0.17em}}f\left(x\right)={x}^{n}\text{,}n\text{\hspace{0.17em}}$
even, are symmetric about the$\text{\hspace{0.17em}}y\text{-}$
axis. In [link] we see that odd functions of the form$\text{\hspace{0.17em}}f\left(x\right)={x}^{n}\text{,}n\text{\hspace{0.17em}}$
odd, are symmetric about the origin.
For these odd power functions, as$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
approaches negative infinity,$\text{\hspace{0.17em}}f\left(x\right)\text{\hspace{0.17em}}$
decreases without bound. As$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
approaches positive infinity,$\text{\hspace{0.17em}}f\left(x\right)\text{\hspace{0.17em}}$
increases without bound. In symbolic form we write
The behavior of the graph of a function as the input values get very small ($\text{\hspace{0.17em}}x\to -\infty \text{\hspace{0.17em}}$
) and get very large ($\text{\hspace{0.17em}}x\to \infty \text{\hspace{0.17em}}$
) is referred to as the end behavior of the function. We can use words or symbols to describe end behavior.
[link] shows the end behavior of power functions in the form$\text{\hspace{0.17em}}f(x)=k{x}^{n}\text{\hspace{0.17em}}$
where$\text{\hspace{0.17em}}n\text{\hspace{0.17em}}$
is a non-negative integer depending on the power and the constant.
**Given a power function$\text{\hspace{0.17em}}f(x)=k{x}^{n}\text{\hspace{0.17em}}$
where**$\text{\hspace{0.17em}}n\text{\hspace{0.17em}}$
is a non-negative integer, identify the end behavior.
Describe the end behavior of the graph of$\text{\hspace{0.17em}}f(x)={x}^{8}.$
The coefficient is 1 (positive) and the exponent of the power function is 8 (an even number). As$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
approaches infinity, the output (value of$\text{\hspace{0.17em}}f(x)\text{\hspace{0.17em}}$
) increases without bound. We write as$\text{\hspace{0.17em}}x\to \infty ,f(x)\to \infty .\text{\hspace{0.17em}}$
As$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
approaches negative infinity, the output increases without bound. In symbolic form, as$x\to -\infty ,f(x)\to \infty .$
We can graphically represent the function as shown in [link].
Describe the end behavior of the graph of$\text{\hspace{0.17em}}f(x)=-{x}^{9}.$
The exponent of the power function is 9 (an odd number). Because the coefficient is$\text{\hspace{0.17em}}\mathrm{\u20131}\text{\hspace{0.17em}}$
(negative), the graph is the reflection about the$\text{\hspace{0.17em}}x\text{-}$
axis of the graph of$\text{\hspace{0.17em}}f(x)={x}^{9}.\text{\hspace{0.17em}}$
[link] shows that as$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
approaches infinity, the output decreases without bound. As$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
approaches negative infinity, the output increases without bound. In symbolic form, we would write
We can check our work by using the table feature on a graphing utility.
$x$ |
$f\left(x\right)$ |
–10 | 1,000,000,000 |
–5 | 1,953,125 |
0 | 0 |
5 | –1,953,125 |
10 | –1,000,000,000 |
We can see from [link] that, when we substitute very small values for$\text{\hspace{0.17em}}x,\text{\hspace{0.17em}}$
the output is very large, and when we substitute very large values for$\text{\hspace{0.17em}}x,\text{\hspace{0.17em}}$
the output is very small (meaning that it is a very large negative value).
Describe in words and symbols the end behavior of$\text{\hspace{0.17em}}f(x)=-5{x}^{4}.$
As$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
approaches positive or negative infinity,$\text{\hspace{0.17em}}f\left(x\right)\text{\hspace{0.17em}}$
decreases without bound: as$\text{\hspace{0.17em}}x\to \pm \infty ,f(x)\to -\infty \text{\hspace{0.17em}}$
because of the negative coefficient.
An oil pipeline bursts in the Gulf of Mexico, causing an oil slick in a roughly circular shape. The slick is currently 24 miles in radius, but that radius is increasing by 8 miles each week. We want to write a formula for the area covered by the oil slick by combining two functions. The radius$\text{\hspace{0.17em}}r\text{\hspace{0.17em}}$
of the spill depends on the number of weeks$\text{\hspace{0.17em}}w\text{\hspace{0.17em}}$
that have passed. This relationship is linear.
We can combine this with the formula for the area$\text{\hspace{0.17em}}A\text{\hspace{0.17em}}$
of a circle.
Composing these functions gives a formula for the area in terms of weeks.
Multiplying gives the formula.
This formula is an example of a polynomial function. A polynomial function consists of either zero or the sum of a finite number of non-zero terms, each of which is a product of a number, called the coefficient of the term, and a variable raised to a non-negative integer power.
Let$\text{\hspace{0.17em}}n\text{\hspace{0.17em}}$
be a non-negative integer. A polynomial function is a function that can be written in the form
This is called the general form of a polynomial function. Each$\text{\hspace{0.17em}}{a}_{i}\text{\hspace{0.17em}}$
is a coefficient and can be any real number, but $\text{\hspace{0.17em}}{a}_{n}\text{\hspace{0.17em}}$
cannot = 0. Each expression$\text{\hspace{0.17em}}{a}_{i}{x}^{i}\text{\hspace{0.17em}}$
is a term of a polynomial function.
Which of the following are polynomial functions?* * *
The first two functions are examples of polynomial functions because they can be written in the form$\text{\hspace{0.17em}}f(x)={a}_{n}{x}^{n}+\mathrm{...}+{a}_{2}{x}^{2}+{a}_{1}x+{a}_{0},\text{\hspace{0.17em}}$
where the powers are non-negative integers and the coefficients are real numbers.
can be written as
$\text{\hspace{0.17em}}f(x)=6{x}^{4}+4.$can be written as
$\text{\hspace{0.17em}}g(x)=-{x}^{3}+4x.$cannot be written in this form and is therefore not a polynomial function.
Because of the form of a polynomial function, we can see an infinite variety in the number of terms and the power of the variable. Although the order of the terms in the polynomial function is not important for performing operations, we typically arrange the terms in descending order of power, or in general form. The degree of the polynomial is the highest power of the variable that occurs in the polynomial; it is the power of the first variable if the function is in general form. The leading term is the term containing the highest power of the variable, or the term with the highest degree. The leading coefficient is the coefficient of the leading term.
We often rearrange polynomials so that the powers are descending.
When a polynomial is written in this way, we say that it is in general form.
Given a polynomial function, identify the degree and leading coefficient.
to determine the degree function.
to find the leading term.
Identify the degree, leading term, and leading coefficient of the following polynomial functions.
For the function$\text{\hspace{0.17em}}f\left(x\right),\text{\hspace{0.17em}}$
the highest power of$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
is 3, so the degree is 3. The leading term is the term containing that degree,$\text{\hspace{0.17em}}\mathrm{-4}{x}^{3}.\text{\hspace{0.17em}}$
The leading coefficient is the coefficient of that term,$\text{\hspace{0.17em}}\mathrm{-4.}$
For the function$\text{\hspace{0.17em}}g\left(t\right),\text{\hspace{0.17em}}$
the highest power of$\text{\hspace{0.17em}}t\text{\hspace{0.17em}}$
is$\text{\hspace{0.17em}}5,\text{\hspace{0.17em}}$
so the degree is$\text{\hspace{0.17em}}5.\text{\hspace{0.17em}}$
The leading term is the term containing that degree,$\text{\hspace{0.17em}}5{t}^{5}.\text{\hspace{0.17em}}$
The leading coefficient is the coefficient of that term,$\text{\hspace{0.17em}}5.$
For the function$\text{\hspace{0.17em}}h\left(p\right),\text{\hspace{0.17em}}$
the highest power of$\text{\hspace{0.17em}}p\text{\hspace{0.17em}}$
is$\text{\hspace{0.17em}}3,\text{\hspace{0.17em}}$
so the degree is$\text{\hspace{0.17em}}3.\text{\hspace{0.17em}}$
The leading term is the term containing that degree,$\text{\hspace{0.17em}}-{p}^{3}.\text{\hspace{0.17em}}$
The leading coefficient is the coefficient of that term,$\text{\hspace{0.17em}}\mathrm{-1.}$
Identify the degree, leading term, and leading coefficient of the polynomial$\text{\hspace{0.17em}}f(x)=4{x}^{2}-{x}^{6}+2x-6.$
The degree is 6. The leading term is$\text{\hspace{0.17em}}-{x}^{6}.\text{\hspace{0.17em}}$
The leading coefficient is$\text{\hspace{0.17em}}-1.$
Knowing the degree of a polynomial function is useful in helping us predict its end behavior. To determine its end behavior, look at the leading term of the polynomial function. Because the power of the leading term is the highest, that term will grow significantly faster than the other terms as$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
gets very large or very small, so its behavior will dominate the graph. For any polynomial, the end behavior of the polynomial will match the end behavior of the power function consisting of the leading term. See [link].
Polynomial Function | Leading Term | Graph of Polynomial Function |
---|---|---|
$f(x)=5{x}^{4}+2{x}^{3}-x-4$ | $5{x}^{4}$ | |
$f(x)=-2{x}^{6}-{x}^{5}+3{x}^{4}+{x}^{3}$ | $-2{x}^{6}$ | |
$f(x)=3{x}^{5}-4{x}^{4}+2{x}^{2}+1$ | $3{x}^{5}$ | |
$f(x)=-6{x}^{3}+7{x}^{2}+3x+1$ | $-6{x}^{3}$ |
Describe the end behavior and determine a possible degree of the polynomial function in [link].
As the input values$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
get very large, the output values$\text{\hspace{0.17em}}f(x)\text{\hspace{0.17em}}$
increase without bound. As the input values$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
get very small, the output values$\text{\hspace{0.17em}}f(x)\text{\hspace{0.17em}}$
decrease without bound. We can describe the end behavior symbolically by writing
In words, we could say that as$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
values approach infinity, the function values approach infinity, and as$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
values approach negative infinity, the function values approach negative infinity.
We can tell this graph has the shape of an odd degree power function that has not been reflected, so the degree of the polynomial creating this graph must be odd and the leading coefficient must be positive.
Describe the end behavior, and determine a possible degree of the polynomial function in [link].
As$\text{\hspace{0.17em}}x\to \infty ,f(x)\to -\infty ;asx\to -\infty ,f(x)\to -\infty .\text{\hspace{0.17em}}$
It has the shape of an even degree power function with a negative coefficient.
Given the function$\text{\hspace{0.17em}}f(x)=-3{x}^{2}(x-1)(x+4),\text{\hspace{0.17em}}$
express the function as a polynomial in general form, and determine the leading term, degree, and end behavior of the function.
Obtain the general form by expanding the given expression for$\text{\hspace{0.17em}}f\left(x\right).$
The general form is$\text{\hspace{0.17em}}f\left(x\right)=\mathrm{-3}{x}^{4}-9{x}^{3}+12{x}^{2}.\text{\hspace{0.17em}}$
The leading term is$\text{\hspace{0.17em}}\mathrm{-3}{x}^{4};\text{\hspace{0.17em}}$
therefore, the degree of the polynomial is 4. The degree is even (4) and the leading coefficient is negative (–3), so the end behavior is
Given the function$\text{\hspace{0.17em}}f(x)=0.2(x-2)(x+1)(x-5),\text{\hspace{0.17em}}$
express the function as a polynomial in general form and determine the leading term, degree, and end behavior of the function.
The leading term is$\text{\hspace{0.17em}}0.2{x}^{3},\text{\hspace{0.17em}}$
so it is a degree 3 polynomial. As$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
approaches positive infinity,$\text{\hspace{0.17em}}f\left(x\right)\text{\hspace{0.17em}}$
increases without bound; as$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
approaches negative infinity,$\text{\hspace{0.17em}}f\left(x\right)\text{\hspace{0.17em}}$
decreases without bound.
In addition to the end behavior of polynomial functions, we are also interested in what happens in the “middle” of the function. In particular, we are interested in locations where graph behavior changes. A turning point is a point at which the function values change from increasing to decreasing or decreasing to increasing.
We are also interested in the intercepts. As with all functions, the y-intercept is the point at which the graph intersects the vertical axis. The point corresponds to the coordinate pair in which the input value is zero. Because a polynomial is a function, only one output value corresponds to each input value so there can be only one y-intercept$\text{\hspace{0.17em}}(0,{a}_{0}).\text{\hspace{0.17em}}$
The x-intercepts occur at the input values that correspond to an output value of zero. It is possible to have more than one x-intercept. See [link].
A turning point of a graph is a point at which the graph changes direction from increasing to decreasing or decreasing to increasing. The y-intercept is the point at which the function has an input value of zero. The x-intercepts are the points at which the output value is zero.
Given a polynomial function, determine the intercepts.
and finding the corresponding output value.
Given the polynomial function$\text{\hspace{0.17em}}f(x)=(x-2)(x+1)(x-4),\text{\hspace{0.17em}}$
written in factored form for your convenience, determine the y- and x-intercepts.
The y-intercept occurs when the input is zero so substitute 0 for$\text{\hspace{0.17em}}x.$
The y-intercept is (0, 8).
The x-intercepts occur when the output is zero.
The x-intercepts are$\text{\hspace{0.17em}}(2,0),(\u20131,0),\text{\hspace{0.17em}}$
and$\text{\hspace{0.17em}}(4,0).$
We can see these intercepts on the graph of the function shown in [link].
Given the polynomial function$\text{\hspace{0.17em}}f(x)={x}^{4}-4{x}^{2}-45,\text{\hspace{0.17em}}$
determine the y- and x-intercepts.
The y-intercept occurs when the input is zero.
The y-intercept is$\text{\hspace{0.17em}}(0,\mathrm{-45}).$
The x-intercepts occur when the output is zero. To determine when the output is zero, we will need to factor the polynomial.
The x-intercepts are$\text{\hspace{0.17em}}(3,0)\text{\hspace{0.17em}}$
and$\text{\hspace{0.17em}}(\mathrm{\u20133},0).$
We can see these intercepts on the graph of the function shown in [link]. We can see that the function is even because$\text{\hspace{0.17em}}f\left(x\right)=f\left(-x\right).$
Given the polynomial function$\text{\hspace{0.17em}}f(x)=2{x}^{3}-6{x}^{2}-20x,\text{\hspace{0.17em}}$
determine the y- and x-intercepts.
y-intercept$\text{\hspace{0.17em}}(0,0);\text{\hspace{0.17em}}$
x-intercepts$\text{\hspace{0.17em}}(0,0),(\u20132,0),\text{\hspace{0.17em}}$
and$(5,0)$
The degree of a polynomial function helps us to determine the number of x-intercepts and the number of turning points. A polynomial function of$\text{\hspace{0.17em}}n\text{th}\text{\hspace{0.17em}}$
degree is the product of$\text{\hspace{0.17em}}n\text{\hspace{0.17em}}$
factors, so it will have at most$\text{\hspace{0.17em}}n\text{\hspace{0.17em}}$
roots or zeros, or x-intercepts. The graph of the polynomial function of degree$\text{\hspace{0.17em}}n\text{\hspace{0.17em}}$
must have at most$\text{\hspace{0.17em}}n\u20131\text{\hspace{0.17em}}$
turning points. This means the graph has at most one fewer turning point than the degree of the polynomial or one fewer than the number of factors.
A continuous function has no breaks in its graph: the graph can be drawn without lifting the pen from the paper. A smooth curve is a graph that has no sharp corners. The turning points of a smooth graph must always occur at rounded curves. The graphs of polynomial functions are both continuous and smooth.
A polynomial of degree$\text{\hspace{0.17em}}n\text{\hspace{0.17em}}$
will have, at most,$\text{\hspace{0.17em}}n\text{\hspace{0.17em}}$
x-intercepts and$\text{\hspace{0.17em}}n-1\text{\hspace{0.17em}}$
turning points.
Without graphing the function, determine the local behavior of the function by finding the maximum number of x-intercepts and turning points for$\text{\hspace{0.17em}}f(x)=-3{x}^{10}+4{x}^{7}-{x}^{4}+2{x}^{3}.$
The polynomial has a degree of$\text{\hspace{0.17em}}10,\text{\hspace{0.17em}}$
so there are at most 10 x-intercepts and at most 9 turning points.
Without graphing the function, determine the maximum number of x-intercepts and turning points for$\text{\hspace{0.17em}}f(x)=108-13{x}^{9}-8{x}^{4}+14{x}^{12}+2{x}^{3}.$
There are at most 12$\text{\hspace{0.17em}}x\text{-}$
intercepts and at most 11 turning points.
What can we conclude about the polynomial represented by the graph shown in [link] based on its intercepts and turning points?
The end behavior of the graph tells us this is the graph of an even-degree polynomial. See [link].
The graph has 2 x-intercepts, suggesting a degree of 2 or greater, and 3 turning points, suggesting a degree of 4 or greater. Based on this, it would be reasonable to conclude that the degree is even and at least 4.
What can we conclude about the polynomial represented by the graph shown in [link] based on its intercepts and turning points?
The end behavior indicates an odd-degree polynomial function; there are 3$\text{\hspace{0.17em}}x\text{-}$
intercepts and 2 turning points, so the degree is odd and at least 3. Because of the end behavior, we know that the lead coefficient must be negative.
Given the function$\text{\hspace{0.17em}}f(x)=-4x\left(x+3\right)\left(x-4\right),\text{\hspace{0.17em}}$
determine the local behavior.
The y-intercept is found by evaluating$\text{\hspace{0.17em}}f(0).$
The y-intercept is$\text{\hspace{0.17em}}(0,0).$
The x-intercepts are found by determining the zeros of the function.
The x-intercepts are$\text{\hspace{0.17em}}(0,0),(\mathrm{\u20133},0),\text{\hspace{0.17em}}$
and$\text{\hspace{0.17em}}(4,0).$
The degree is 3 so the graph has at most 2 turning points.
Given the function$\text{\hspace{0.17em}}f(x)=0.2(x-2)(x+1)(x-5),\text{\hspace{0.17em}}$
determine the local behavior.
The$\text{\hspace{0.17em}}x\text{-}$
intercepts are$\text{\hspace{0.17em}}(2,0),(-1,0),$
and$\text{\hspace{0.17em}}(5,0),\text{\hspace{0.17em}}$
the y-intercept is$\text{\hspace{0.17em}}(0,\text{2}),\text{\hspace{0.17em}}$
and the graph has at most 2 turning points.
Access these online resources for additional instruction and practice with power and polinomial functions.
[Turning Points and$\text{\hspace{0.17em}}x\text{-}$
intercepts of Polynomial Functions]3
general form of a polynomial function | $$f(x)={a}_{n}{x}^{n}+\mathrm{...}+{a}_{2}{x}^{2}+{a}_{1}x+{a}_{0}$$ |
will have at most
$\text{\hspace{0.17em}}n\text{\hspace{0.17em}}$x-intercepts and at most
$\text{\hspace{0.17em}}n-1\text{\hspace{0.17em}}$turning points. See [link], [link], [link], [link], and [link].
Explain the difference between the coefficient of a power function and its degree.
The coefficient of the power function is the real number that is multiplied by the variable raised to a power. The degree is the highest power appearing in the function.
If a polynomial function is in factored form, what would be a good first step in order to determine the degree of the function?
In general, explain the end behavior of a power function with odd degree if the leading coefficient is positive.
As$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
decreases without bound, so does$\text{\hspace{0.17em}}f\left(x\right).\text{\hspace{0.17em}}$
As$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
increases without bound, so does$\text{\hspace{0.17em}}f\left(x\right).$
What is the relationship between the degree of a polynomial function and the maximum number of turning points in its graph?
What can we conclude if, in general, the graph of a polynomial function exhibits the following end behavior? As$\text{\hspace{0.17em}}x\to -\infty ,\text{\hspace{0.17em}}f(x)\to -\infty \text{\hspace{0.17em}}$
and as$\text{\hspace{0.17em}}x\to \infty ,\text{\hspace{0.17em}}f(x)\to -\infty .\text{\hspace{0.17em}}$
The polynomial function is of even degree and leading coefficient is negative.
For the following exercises, identify the function as a power function, a polynomial function, or neither.
Power function
Neither
Neither
For the following exercises, find the degree and leading coefficient for the given polynomial.
Degree = 2, Coefficient = –2
Degree =4, Coefficient = –2
For the following exercises, determine the end behavior of the functions.
For the following exercises, find the intercepts of the functions.
y-intercept is$\text{\hspace{0.17em}}(0,12),\text{\hspace{0.17em}}$
t-intercepts are$\text{\hspace{0.17em}}(1,0);(\u20132,0);\text{and}(3,0).$
y-intercept is$\text{\hspace{0.17em}}(0,-16).\text{\hspace{0.17em}}$
x-intercepts are$\text{\hspace{0.17em}}(2,0)\text{\hspace{0.17em}}$
and$\text{\hspace{0.17em}}(-2,0).$
y-intercept is$\text{\hspace{0.17em}}(0,0).\text{\hspace{0.17em}}$
x-intercepts are$\text{\hspace{0.17em}}(0,0),(4,0),\text{\hspace{0.17em}}$
and$\text{\hspace{0.17em}}\left(-2,0\right).$
For the following exercises, determine the least possible degree of the polynomial function shown.
3
5
3
5
For the following exercises, determine whether the graph of the function provided is a graph of a polynomial function. If so, determine the number of turning points and the least possible degree for the function.
Yes. Number of turning points is 2. Least possible degree is 3.
Yes. Number of turning points is 1. Least possible degree is 2.
Yes. Number of turning points is 0. Least possible degree is 1.
No.
Yes. Number of turning points is 0. Least possible degree is 1.
For the following exercises, make a table to confirm the end behavior of the function.
$x$ | $f\left(x\right)$ |
---|---|
10 | 9,500 |
100 | 99,950,000 |
–10 | 9,500 |
–100 | 99,950,000 |
$x$ | $f\left(x\right)$ |
---|---|
10 | –504 |
100 | –941,094 |
–10 | 1,716 |
–100 | 1,061,106 |
For the following exercises, graph the polynomial functions using a calculator. Based on the graph, determine the intercepts and the end behavior.
The$\text{\hspace{0.17em}}y\text{-}$
intercept is$\text{\hspace{0.17em}}\left(0,0\right).\text{\hspace{0.17em}}$
The$\text{\hspace{0.17em}}x\text{-}$
intercepts are$\text{\hspace{0.17em}}\left(0,0\right),\text{}\left(2,0\right).\text{\hspace{0.17em}}$
$\text{As}\text{\hspace{0.17em}}x\to -\infty ,\text{\hspace{0.17em}}\text{\hspace{0.17em}}f(x)\to \infty ,\text{\hspace{0.17em}}\text{as}\text{\hspace{0.17em}}x\to \infty ,\text{\hspace{0.17em}}f(x)\to \infty $The$\text{\hspace{0.17em}}y\text{-}$
intercept is$\text{\hspace{0.17em}}\left(0,0\right)$
. The$\text{\hspace{0.17em}}x\text{-}$
intercepts are$\text{\hspace{0.17em}}\left(0,0\right),\text{}\left(5,0\right),\text{}\left(7,0\right).\text{\hspace{0.17em}}$
$\text{As}\text{\hspace{0.17em}}x\to -\infty ,\text{\hspace{0.17em}}\text{\hspace{0.17em}}f(x)\to -\infty ,\text{\hspace{0.17em}}\text{as}\text{\hspace{0.17em}}x\to \infty ,\text{\hspace{0.17em}}f(x)\to \infty $The$\text{\hspace{0.17em}}y\text{-}$
intercept is$\text{\hspace{0.17em}}\left(0,0\right).\text{\hspace{0.17em}}$
The$\text{\hspace{0.17em}}x\text{-}$
intercept is$\text{\hspace{0.17em}}\left(-4,0\right),\text{}\left(0,0\right),\text{}\left(4,0\right).\text{\hspace{0.17em}}$
$As\text{\hspace{0.17em}}x\to -\infty ,\text{\hspace{0.17em}}\text{\hspace{0.17em}}f(x)\to -\infty ,\text{\hspace{0.17em}}\text{as}\text{\hspace{0.17em}}x\to \infty ,\text{\hspace{0.17em}}f(x)\to \infty $The$\text{\hspace{0.17em}}y\text{-}$
intercept is$\text{\hspace{0.17em}}\left(0,-81\right).\text{\hspace{0.17em}}$
The$\text{\hspace{0.17em}}x\text{-}$
intercept are$\text{\hspace{0.17em}}\left(3,0\right),\text{}\left(-3,0\right).\text{\hspace{0.17em}}$
$\text{As}\text{\hspace{0.17em}}x\to -\infty ,\text{\hspace{0.17em}}\text{\hspace{0.17em}}f(x)\to \infty ,\text{\hspace{0.17em}}\text{as}\text{\hspace{0.17em}}x\to \infty ,\text{\hspace{0.17em}}f(x)\to \infty $The$\text{\hspace{0.17em}}y\text{-}$
intercept is$\text{\hspace{0.17em}}\left(0,0\right).\text{\hspace{0.17em}}$
The$\text{\hspace{0.17em}}x\text{-}$
intercepts are$\text{\hspace{0.17em}}\left(-3,0\right),\text{}\left(0,0\right),\text{}\left(5,0\right).\text{\hspace{0.17em}}$
$\text{As}\text{\hspace{0.17em}}x\to -\infty ,\text{\hspace{0.17em}}\text{\hspace{0.17em}}f(x)\to -\infty ,\text{\hspace{0.17em}}\text{as}\text{\hspace{0.17em}}x\to \infty ,\text{\hspace{0.17em}}f(x)\to \infty $For the following exercises, use the information about the graph of a polynomial function to determine the function. Assume the leading coefficient is 1 or –1. There may be more than one correct answer.
The$\text{\hspace{0.17em}}y-$
intercept is$\text{\hspace{0.17em}}(0,-4).\text{\hspace{0.17em}}$
The$\text{\hspace{0.17em}}x-$
intercepts are$\text{\hspace{0.17em}}(-2,0),\text{\hspace{0.17em}}(2,0).\text{\hspace{0.17em}}$
Degree is 2.
End behavior:$\text{\hspace{0.17em}}\text{as}\text{\hspace{0.17em}}x\to -\infty ,\text{\hspace{0.17em}}\text{\hspace{0.17em}}f(x)\to \infty ,\text{\hspace{0.17em}}\text{as}\text{\hspace{0.17em}}x\to \infty ,\text{\hspace{0.17em}}f(x)\to \infty .$
The$\text{\hspace{0.17em}}y-$
intercept is$\text{\hspace{0.17em}}(0,9).\text{\hspace{0.17em}}$
The$\text{\hspace{0.17em}}x\text{-}$
intercepts are$\text{\hspace{0.17em}}(-3,0),\text{\hspace{0.17em}}(3,0).\text{\hspace{0.17em}}$
Degree is 2.
End behavior:$\text{\hspace{0.17em}}\text{as}\text{\hspace{0.17em}}x\to -\infty ,\text{\hspace{0.17em}}\text{\hspace{0.17em}}f(x)\to -\infty ,\text{\hspace{0.17em}}\text{as}\text{\hspace{0.17em}}x\to \infty ,\text{\hspace{0.17em}}f(x)\to -\infty .$
The$\text{\hspace{0.17em}}y-$
intercept is$\text{\hspace{0.17em}}(0,0).\text{\hspace{0.17em}}$
The$\text{\hspace{0.17em}}x-$
intercepts are$\text{\hspace{0.17em}}(0,0),\text{\hspace{0.17em}}(2,0).\text{\hspace{0.17em}}$
Degree is 3.
End behavior:$\text{\hspace{0.17em}}\text{as}\text{\hspace{0.17em}}x\to -\infty ,\text{\hspace{0.17em}}\text{\hspace{0.17em}}f(x)\to -\infty ,\text{\hspace{0.17em}}\text{as}\text{\hspace{0.17em}}x\to \infty ,\text{\hspace{0.17em}}f(x)\to \infty .$
The$\text{\hspace{0.17em}}y-$
intercept is$\text{\hspace{0.17em}}(0,1).\text{\hspace{0.17em}}$
The$\text{\hspace{0.17em}}x-$
intercept is$\text{\hspace{0.17em}}(1,0).\text{\hspace{0.17em}}$
Degree is 3.
End behavior:$\text{\hspace{0.17em}}\text{as}\text{\hspace{0.17em}}x\to -\infty ,\text{\hspace{0.17em}}\text{\hspace{0.17em}}f(x)\to \infty ,\text{\hspace{0.17em}}\text{as}\text{\hspace{0.17em}}x\to \infty ,\text{\hspace{0.17em}}f(x)\to -\infty .$
The$\text{\hspace{0.17em}}y-$
intercept is$\text{\hspace{0.17em}}(0,1).\text{\hspace{0.17em}}$
There is no$\text{\hspace{0.17em}}x-$
intercept. Degree is 4.
End behavior:$\text{\hspace{0.17em}}\text{as}\text{\hspace{0.17em}}x\to -\infty ,\text{\hspace{0.17em}}\text{\hspace{0.17em}}f(x)\to \infty ,\text{\hspace{0.17em}}\text{as}\text{\hspace{0.17em}}x\to \infty ,\text{\hspace{0.17em}}f(x)\to \infty .$
For the following exercises, use the written statements to construct a polynomial function that represents the required information.
An oil slick is expanding as a circle. The radius of the circle is increasing at the rate of 20 meters per day. Express the area of the circle as a function of$\text{\hspace{0.17em}}d,\text{\hspace{0.17em}}$
the number of days elapsed.
A cube has an edge of 3 feet. The edge is increasing at the rate of 2 feet per minute. Express the volume of the cube as a function of$\text{\hspace{0.17em}}m,\text{\hspace{0.17em}}$
the number of minutes elapsed.
A rectangle has a length of 10 inches and a width of 6 inches. If the length is increased by$\text{\hspace{0.17em}}x\text{\hspace{0.17em}}$
inches and the width increased by twice that amount, express the area of the rectangle as a function of$\text{\hspace{0.17em}}x.$
An open box is to be constructed by cutting out square corners of $\text{\hspace{0.17em}}x-$
inch sides from a piece of cardboard 8 inches by 8 inches and then folding up the sides. Express the volume of the box as a function of$\text{\hspace{0.17em}}x.$
A rectangle is twice as long as it is wide. Squares of side 2 feet are cut out from each corner. Then the sides are folded up to make an open box. Express the volume of the box as a function of the width ($x$
).
where
$\text{\hspace{0.17em}}k\text{\hspace{0.17em}}$is a constant, the base is a variable, and the exponent,
$\text{\hspace{0.17em}}p$, is a constant
of a polynomial function in the form
$\text{\hspace{0.17em}}f(x)={a}_{n}{x}^{n}+\mathrm{...}+{a}_{2}{x}^{2}+{a}_{1}x+{a}_{0}$You can also download for free at http://cnx.org/contents/13ac107a-f15f-49d2-97e8-60ab2e3b519c@11.1
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