Use the Properties of Logarithms

By the end of this section, you will be able to:

Before you get started, take this readiness quiz.

  1. Evaluate: a0

    a1.

    If you missed this problem, review [link].

  2. Write with a rational exponent: x2y3.

    If you missed this problem, review [link].

  3. Round to three decimal places: 2.5646415.

    If you missed this problem, review [link].

Use the Properties of Logarithms

Now that we have learned about exponential and logarithmic functions, we can introduce some of the properties of logarithms. These will be very helpful as we continue to solve both exponential and logarithmic equations.

The first two properties derive from the definition of logarithms. Since a0=1,

we can convert this to logarithmic form and get loga1=0.

Also, since a1=a,

we get logaa=1.

Properties of Logarithms
loga1=0logaa=1

In the next example we could evaluate the logarithm by converting to exponential form, as we have done previously, but recognizing and then applying the properties saves time.

Evaluate using the properties of logarithms: log81

and log66.

* * *

log81Use the property,loga1=0.0log81=0

* * *

log66Use the property,logaa=1.1log66=1

Evaluate using the properties of logarithms: log131

log99.

0 1

Evaluate using the properties of logarithms: log51

log77.

0 1

The next two properties can also be verified by converting them from exponential form to logarithmic form, or the reverse.

The exponential equation alogax=x

converts to the logarithmic equation logax=logax,

which is a true statement for positive values for x only.

The logarithmic equation logaax=x

converts to the exponential equation ax=ax,

which is also a true statement.

These two properties are called inverse properties because, when we have the same base, raising to a power “undoes” the log and taking the log “undoes” raising to a power. These two properties show the composition of functions. Both ended up with the identity function which shows again that the exponential and logarithmic functions are inverse functions.

Inverse Properties of Logarithms

For a>0,

x>0

and a1,

alogax=xlogaax=x

In the next example, apply the inverse properties of logarithms.

Evaluate using the properties of logarithms: 4log49

and log335.

* * *

4log49 Use the property,alogax=x.94log49=9

* * *

log335 Use the property,alogax=x.5log335=5

Evaluate using the properties of logarithms: 5log515

log774.

15 4

Evaluate using the properties of logarithms: 2log28

log2215.

8 15

There are three more properties of logarithms that will be useful in our work. We know exponential functions and logarithmic function are very interrelated. Our definition of logarithm shows us that a logarithm is the exponent of the equivalent exponential. The properties of exponents have related properties for exponents.

In the Product Property of Exponents, am·an=am+n,

we see that to multiply the same base, we add the exponents. The Product Property of Logarithms, logaM·N=logaM+logaN

tells us to take the log of a product, we add the log of the factors.

Product Property of Logarithms

If M>0,N>0,a>0

and a1,

then,

loga(M·N)=logaM+logaN

The logarithm of a product is the sum of the logarithms.

We use this property to write the log of a product as a sum of the logs of each factor.

Use the Product Property of Logarithms to write each logarithm as a sum of logarithms. Simplify, if possible: log37x

and log464xy.

* * *

log37x Use the Product Property,loga(M·N)=logaM+logaN.log37+log3x log37x=log37+log3x

* * *

log464xy Use the Product Property,loga(M·N)=logaM+logaN.log464+log4x+log4y Simplify by evaluatinglog464.3+log4x+log4y log464xy=3+log4x+log4y

Use the Product Property of Logarithms to write each logarithm as a sum of logarithms. Simplify, if possible.

log33x

log28xy

1+log3x


3+log2x+log2y

Use the Product Property of Logarithms to write each logarithm as a sum of logarithms. Simplify, if possible.

log99x

log327xy

1+log9x


3+log3x+log3y

Similarly, in the Quotient Property of Exponents, aman=amn,

we see that to divide the same base, we subtract the exponents. The Quotient Property of Logarithms, logaMN=logaMlogaN

tells us to take the log of a quotient, we subtract the log of the numerator and denominator.

Quotient Property of Logarithms

If M>0,N>0,a>0

and a1,

then,

logaMN=logaMlogaN

The logarithm of a quotient is the difference of the logarithms.

Note that logaMlogaNloga(MN).

We use this property to write the log of a quotient as a difference of the logs of each factor.

Use the Quotient Property of Logarithms to write each logarithm as a difference of logarithms. Simplify, if possible.* * *

log557

and logx100

* * *

log557 Use the Quotient Property,logaMN=logaMlogaN.log55log57 Simplify.1log57 log557=1log57

* * *

logx100Use the Quotient Property,logaMN=logaMlogaN.logxlog100 Simplify.logx2 logx100=logx2

Use the Quotient Property of Logarithms to write each logarithm as a difference of logarithms. Simplify, if possible.

log434

logx1000

log431

logx3

Use the Quotient Property of Logarithms to write each logarithm as a difference of logarithms. Simplify, if possible.

log254

log10y

log252

1logy

The third property of logarithms is related to the Power Property of Exponents, (am)n=am·n,

we see that to raise a power to a power, we multiply the exponents. The Power Property of Logarithms, logaMp=plogaM

tells us to take the log of a number raised to a power, we multiply the power times the log of the number.

Power Property of Logarithms

If M>0,a>0,a1

and p

is any real number then,

logaMp=plogaM

The log of a number raised to a power as the product product of the power times the log of the number.

We use this property to write the log of a number raised to a power as the product of the power times the log of the number. We essentially take the exponent and throw it in front of the logarithm.

Use the Power Property of Logarithms to write each logarithm as a product of logarithms. Simplify, if possible.* * *

log543

and logx10

* * *

log543 Use the Power Property,logaMp=plogaM.3log54 log543=3log54

* * *

logx10 Use the Power Property,logaMp=plogaM.10logx logx10=10logx

Use the Power Property of Logarithms to write each logarithm as a product of logarithms. Simplify, if possible.

log754

logx100

4log75

100·logx

Use the Power Property of Logarithms to write each logarithm as a product of logarithms. Simplify, if possible.

log237

logx20

7log23

20·logx

We summarize the Properties of Logarithms here for easy reference. While the natural logarithms are a special case of these properties, it is often helpful to also show the natural logarithm version of each property.

Properties of Logarithms

If M>0,a>0,a1

and p

is any real number then,

Property Base a
Base e
   
{: valign=”top”} ———-
  loga1=0
ln1=0
     
{: valign=”top”}   logaa=1
lne=1
     
{: valign=”top”} Inverse Properties alogax=xlogaax=x
elnx=x lnex=x
     
{: valign=”top”} Product Property of Logarithms loga(M·N)=logaM+logaN
ln(M·N)=lnM+lnN
     
{: valign=”top”} Quotient Property of Logarithms logaMN=logaMlogaN
lnMN=lnMlnN
     
{: valign=”top”} Power Property of Logarithms logaMp=plogaM
lnMp=plnM

| {: valign=”top”}{: .unnumbered summary=”.” data-label=””}

Now that we have the properties we can use them to “expand” a logarithmic expression. This means to write the logarithm as a sum or difference and without any powers.

We generally apply the Product and Quotient Properties before we apply the Power Property.

Use the Properties of Logarithms to expand the logarithm log4(2x3y2)

. Simplify, if possible.

log4(2x3y2) Use the Product Property,logaM·N=logaM+logaN.log42+log4x3+log4y2 Use the Power Property,logaMp=plogaM,on the last two terms.log42+3log4x+2log4y Simplify.12+3log4x+2log4y log4(2x3y2)=12+3log4x+2log4y

Use the Properties of Logarithms to expand the logarithm log2(5x4y2)

. Simplify, if possible.

log25+4log2x+2log2y

Use the Properties of Logarithms to expand the logarithm log3(7x5y3)

. Simplify, if possible.

log37+5log3x+3log3y

When we have a radical in the logarithmic expression, it is helpful to first write its radicand as a rational exponent.

Use the Properties of Logarithms to expand the logarithm log2x33y2z4

. Simplify, if possible.

log2x33y2z4 Rewrite the radical with a rational exponent.log2(x33y2z)14 Use the Power Property,logaMp=plogaM.14log2(x33y2z) Use the Quotient Property,logaM·N=logaMlogaN.14(log2(x3)log2(3y2z)) Use the Product Property,logaM·N=logaM+logaN,in the second term.14(log2(x3)(log23+log2y2+log2z)) Use the Power Property,logaMp=plogaM,inside the parentheses.14(3log2x(log23+2log2y+log2z)) Simplify by distributing.14(3log2xlog232log2ylog2z) log2x33y2z4=14(3log2xlog232log2ylog2z)

Use the Properties of Logarithms to expand the logarithm log4x42y3z25

. Simplify, if possible.

15(4log4x123log4y2log4z)

Use the Properties of Logarithms to expand the logarithm log3x25yz3

. Simplify, if possible.

13(2log3xlog35log3ylog3z)

The opposite of expanding a logarithm is to condense a sum or difference of logarithms that have the same base into a single logarithm. We again use the properties of logarithms to help us, but in reverse.

To condense logarithmic expressions with the same base into one logarithm, we start by using the Power Property to get the coefficients of the log terms to be one and then the Product and Quotient Properties as needed.

Use the Properties of Logarithms to condense the logarithm log43+log4xlog4y

. Simplify, if possible.

The log expressions all have the same base, 4.log43+log4xlog4y The first two terms are added, so we use the Product Property,logaM+logaN=logaM·N.log43xlog4y Since the logs are subtracted, we use the Quotient Property,logaMlogaN=logaMN.log43xy log43+log4xlog4y=log43xy

Use the Properties of Logarithms to condense the logarithm log25+log2xlog2y

. Simplify, if possible.

log25xy

Use the Properties of Logarithms to condense the logarithm log36log3xlog3y

. Simplify, if possible.

log36xy

Use the Properties of Logarithms to condense the logarithm 2log3x+4log3(x+1)

. Simplify, if possible.

The log expressions have the same base, 3.2log3x+4log3(x+1) Use the Power Property,logaM+logaN=logaM·N.log3x2+log3(x+1)4 The terms are added, so we use the ProductProperty,logaM+logaN=logaM·N.log3x2(x+1)4 2log3x+4log3(x+1)=log3x2(x+1)4

Use the Properties of Logarithms to condense the logarithm 3log2x+2log2(x1)

. Simplify, if possible.

log2x3(x1)2

Use the Properties of Logarithms to condense the logarithm 2logx+2log(x+1)

. Simplify, if possible.

logx2(x+1)2

Use the Change-of-Base Formula

To evaluate a logarithm with any other base, we can use the Change-of-Base Formula. We will show how this is derived.

Suppose we want to evaluatelogaM.logaM Lety=logaM.y=logaM Rewrite the expression in exponential form.ay=M Take thelogbof each side.logbay=logbM Use the Power Property.ylogba=logbM Solve fory.y=logbMlogba Substitutey=logaM.logaM=logbMlogba

The Change-of-Base Formula introduces a new base b.

This can be any base b we want where b>0,b1.

Because our calculators have keys for logarithms base 10 and base e, we will rewrite the Change-of-Base Formula with the new base as 10 or e.

Change-of-Base Formula

For any logarithmic bases a,b

and M>0,

logaM=logbMlogbalogaM=logMlogalogaM=lnMlna new basebnew base 10new basee

When we use a calculator to find the logarithm value, we usually round to three decimal places. This gives us an approximate value and so we use the approximately equal symbol (≈)

.

Rounding to three decimal places, approximate log435.

.
Use the Change-of-Base Formula. .
Identify a and M. Choose 10 for b. .
Enter the expression log35log4 in the calculator
using the log button for base 10. Round to three decimal places.
.

Rounding to three decimal places, approximate log342.

3.402

Rounding to three decimal places, approximate log546.

2.379

Access these online resources for additional instruction and practice with using the properties of logarithms.

Key Concepts


logaM=logbMlogbalogaM=logMlogalogaM=lnMlna new basebnew base 10new basee

Practice Makes Perfect

Use the Properties of Logarithms

In the following exercises, use the properties of logarithms to evaluate.

log41

log88

log121

lne

0 1

3log36

log227

5log510

log4410

10 10

8log87

log66−2

6log615

log88−4

15 −4

10log5

log10−2

10log3

log10−1

3

−1

eln4

lne2

eln3

lne7

3 7

In the following exercises, use the Product Property of Logarithms to write each logarithm as a sum of logarithms. Simplify if possible.

log46x
log58y
log58+log5y
log232xy
log381xy
4+log3x+log3y
log100x
log1000y
3+logy

In the following exercises, use the Quotient Property of Logarithms to write each logarithm as a sum of logarithms. Simplify if possible.

log338
log656
log651
log416y
log5125x
3log5x
logx10
log10,000y
4logy
lne33
lne416
4ln16

In the following exercises, use the Power Property of Logarithms to expand each. Simplify if possible.

log3x2
log2x5
5log2x
logx−2
logx−3
−3logx
log4x
log5x3
13log5x
lnx3
lnx43
43lnx

In the following exercises, use the Properties of Logarithms to expand the logarithm. Simplify if possible.

log5(4x6y4)
log2(3x5y3)
log23+5log2x+3log2y
log3(2x2)
log5(214y3)
14log521+3log5y
log3xy2z2
log54ab3c4d2
log54+log5a+3log5b
+4log5c2log5d
log4x16y4
log3x2327y4
23log3x34log3y
log22x+y2z2
log33x+2y25z2
12log3(3x+2y2)log352log3z
log25x32y2z44
log53x24y3z3
13(log53+2log5xlog54
3log5ylog5z)

In the following exercises, use the Properties of Logarithms to condense the logarithm. Simplify if possible.

log64+log69
log4+log25

2

log280log25
log336log34

2

log34+log3(x+1)
log25log2(x1)
log25x1
log73+log7xlog7y
log52log5xlog5y
log52xy
4log2x+6log2y
6log3x+9log3y
log3x6y9
log3(x21)2log3(x1)
log(x2+2x+1)2log(x+1)

0

4logx2logy3logz
3lnx+4lny2lnz
lnx3y4z2
13logx3log(x+1)
2log(2x+3)+12log(x+1)
log(2x+3)2·x+1

Use the Change-of-Base Formula

In the following exercises, use the Change-of-Base Formula, rounding to three decimal places, to approximate each logarithm.

log342
log546
2.379
log1287
log1593
1.674
log217
log321
5.542

Writing Exercises

Write the Product Property in your own words. Does it apply to each of the following? loga5x,

loga(5+x).

Why or why not?

Write the Power Property in your own words. Does it apply to each of the following? logaxp,

(logax)r.

Why or why not?

Answers will vary.

Use an example to show that* * *

log(a+b)loga+logb?

Explain how to find the value of log715

using your calculator.

Answers will vary.

Self Check

After completing the exercises, use this checklist to evaluate your mastery of the objectives of this section.

This table has three rows and four columns. The first row, which serves as a header, reads I can…, Confidently, With some help, and No—I don’t get it. The first column below the header row reads use the properties of logarithms and use the change of base formula. The rest of the cells are blank. On a scale of 110,

how would you rate your mastery of this section in light of your responses on the checklist? How can you improve this?


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